Difference between revisions of "2008 AMC 12A Problems/Problem 6"
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==Solution== | ==Solution== | ||
+ | ===Solution 1=== | ||
Let the sticker price be <math>x</math>. | Let the sticker price be <math>x</math>. | ||
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Solving, we find <math>x=750</math>, and the thus answer is <math>\mathrm{(A)}</math>. | Solving, we find <math>x=750</math>, and the thus answer is <math>\mathrm{(A)}</math>. | ||
+ | |||
+ | ===Solution 2=== | ||
+ | The <math>\</math><math>90</math> in store <math>A</math> is <math>\</math><math>15</math> better than the additional <math>10\%</math> off at store <math>B</math>. | ||
+ | |||
+ | Thus the <math>10\%</math> off is equal to <math>\</math><math>90</math> <math>-</math> <math>\</math><math>15</math> <math>=</math> <math>\</math><math>75</math>, and therefore the sticker price is <math>\</math><math>750</math>. | ||
==See Also== | ==See Also== |
Revision as of 15:42, 5 January 2009
- The following problem is from both the 2008 AMC 12A #6 and 2004 AMC 10A #8, so both problems redirect to this page.
Problem
Heather compares the price of a new computer at two different stores. Store offers off the sticker price followed by a rebate, and store offers off the same sticker price with no rebate. Heather saves by buying the computer at store instead of store . What is the sticker price of the computer, in dollars?
Solution
Solution 1
Let the sticker price be .
The price of the computer is at store , and at store .
Heather saves at store , so .
Solving, we find , and the thus answer is .
Solution 2
The in store is better than the additional off at store .
Thus the off is equal to , and therefore the sticker price is .
See Also
2008 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 5 |
Followed by Problem 7 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
2008 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |