Difference between revisions of "2007 AMC 12B Problems/Problem 1"

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{{duplicate|[[2007 AMC 12B Problems|2007 AMC 12B #1]] and [[2007 AMC 10B Problems|2007 AMC 10B #1]]}}
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==Problem==
 
==Problem==
  
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==See Also==
 
==See Also==
 
{{AMC12 box|year=2007|ab=B|before=First question|num-a=2}}
 
{{AMC12 box|year=2007|ab=B|before=First question|num-a=2}}
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{{AMC10 box|year=2007|ab=B|before=First<br />Problem|num-a=2}}
 
[[Category:Introductory Geometry Problems]]
 
[[Category:Introductory Geometry Problems]]

Revision as of 22:07, 11 July 2009

The following problem is from both the 2007 AMC 12B #1 and 2007 AMC 10B #1, so both problems redirect to this page.

Problem

Isabella's house has 3 bedrooms. Each bedroom is 12 feet long, 10 feet wide, and 8 feet high. Isabella must paint the walls of all the bedrooms. Doorways and windows, which will not be painted, occupy 60 square feet in each bedroom. How many square feet of walls must be painted?

$\mathrm{(A)}\ 678 \qquad \mathrm{(B)}\ 768 \qquad \mathrm{(C)}\ 786 \qquad \mathrm{(D)}\ 867 \qquad \mathrm{(E)}\ 876$

Solution

There are four walls in each bedroom, since she can't paint floors or ceilings. So we calculate the number of square feet of wall there is in one bedroom: \[12*8+12*8+10*8+10*8-60=160+192-60=292\] We have three bedrooms, so she must paint $292*3=876 \Rightarrow \mathrm {(E)}$ square feet of wall.

See Also

2007 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
First question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions
2007 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
First
Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions