Difference between revisions of "1988 AJHSME Problems/Problem 9"

m
Line 28: Line 28:
 
{{AJHSME box|year=1988|num-b=8|num-a=10}}
 
{{AJHSME box|year=1988|num-b=8|num-a=10}}
 
[[Category:Introductory Geometry Problems]]
 
[[Category:Introductory Geometry Problems]]
 +
{{MAA Notice}}

Revision as of 22:55, 4 July 2013

Problem

An isosceles triangle is a triangle with two sides of equal length. How many of the five triangles on the square grid below are isosceles?

[asy] for(int a=0; a<12; ++a)  {   draw((a,0)--(a,6));  } for(int b=0; b<7; ++b)  {   draw((0,b)--(11,b));  } draw((0,6)--(2,6)--(1,4)--cycle,linewidth(1)); draw((3,4)--(3,6)--(5,4)--cycle,linewidth(1)); draw((0,1)--(3,2)--(6,1)--cycle,linewidth(1)); draw((7,4)--(6,6)--(9,4)--cycle,linewidth(1)); draw((8,1)--(9,3)--(10,0)--cycle,linewidth(1)); [/asy]

$\text{(A)}\ 1 \qquad \text{(B)}\ 2 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 4 \qquad \text{(E)}\ 5$

Solution

The first triangle has two legs of length $\sqrt{2^2+1^2}$, the second has two legs of length 2, the leg lengths of the third triangle are $2$, $\sqrt{5}$, and $\sqrt{13}$, two legs of the fourth triangle have length $\sqrt{3^2+1^2}$, and two legs of the fifth triangle have length $\sqrt{1^2+2^2}$. Therefore all of the triangles in the diagram except the third are isosceles, and there are $4\Rightarrow \mathrm{(D)}$ are isosceles.

See Also

1988 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png