Difference between revisions of "1991 USAMO Problems"

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In triangle <math>\, ABC, \,</math> angle <math>\,A\,</math> is twice angle <math>\,B,\,</math> angle <math>\,C\,</math> is obtuse, and the three side lengths <math>\,a,b,c\,</math> are integers.  Determine, with proof, the minimum possible perimeter.
 
In triangle <math>\, ABC, \,</math> angle <math>\,A\,</math> is twice angle <math>\,B,\,</math> angle <math>\,C\,</math> is obtuse, and the three side lengths <math>\,a,b,c\,</math> are integers.  Determine, with proof, the minimum possible perimeter.
  
* [[1991 USAMO Problems/Problem 1 | Solution]]
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[[1991 USAMO Problems/Problem 1 | Solution]]
  
 
== Problem 2 ==
 
== Problem 2 ==
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where "<math>\Sigma</math>" denotes a sum involving all nonempty subsets <math>S</math> of <math>\{1,2,3, \ldots,n\}</math>.
 
where "<math>\Sigma</math>" denotes a sum involving all nonempty subsets <math>S</math> of <math>\{1,2,3, \ldots,n\}</math>.
  
* [[1991 USAMO Problems/Problem 2 | Solution]]
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[[1991 USAMO Problems/Problem 2 | Solution]]
  
 
== Problem 3 ==
 
== Problem 3 ==
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[The tower of exponents is defined by <math>a_1 = 2, \; a_{i+1} = 2^{a_i}</math>. Also <math>a_i \pmod{n}</math> means the remainder which results from dividing <math>\,a_i\,</math> by <math>\,n</math>.]
 
[The tower of exponents is defined by <math>a_1 = 2, \; a_{i+1} = 2^{a_i}</math>. Also <math>a_i \pmod{n}</math> means the remainder which results from dividing <math>\,a_i\,</math> by <math>\,n</math>.]
  
* [[1991 USAMO Problems/Problem 3 | Solution]]
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[[1991 USAMO Problems/Problem 3 | Solution]]
  
 
== Problem 4 ==
 
== Problem 4 ==
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[You may wish to analyze the ratio <math>\,(a^N - N^N)/(a-N),</math> for real <math>\, a \geq 0 \,</math> and integer <math>\, N \geq 1</math>.]
 
[You may wish to analyze the ratio <math>\,(a^N - N^N)/(a-N),</math> for real <math>\, a \geq 0 \,</math> and integer <math>\, N \geq 1</math>.]
  
* [[1991 USAMO Problems/Problem 4 | Solution]]
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[[1991 USAMO Problems/Problem 4 | Solution]]
  
 
== Problem 5 ==
 
== Problem 5 ==
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</center>
 
</center>
  
* [[1991 USAMO Problems/Problem 5 | Solution]]
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[[1991 USAMO Problems/Problem 5 | Solution]]
  
== Resources ==
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== See Also ==
  
 
{{USAMO box|year=1991|before=[[1990 USAMO]]|after=[[1992 USAMO]]}}
 
{{USAMO box|year=1991|before=[[1990 USAMO]]|after=[[1992 USAMO]]}}

Latest revision as of 18:17, 18 July 2016

Problems from the 1991 USAMO. There were five questions administered in one three-and-a-half-hour session.

Problem 1

In triangle $\, ABC, \,$ angle $\,A\,$ is twice angle $\,B,\,$ angle $\,C\,$ is obtuse, and the three side lengths $\,a,b,c\,$ are integers. Determine, with proof, the minimum possible perimeter.

Solution

Problem 2

For any nonempty set $\,S\,$ of numbers, let $\,\sigma(S)\,$ and $\,\pi(S)\,$ denote the sum and product, respectively, of the elements of $\,S\,$. Prove that \[\sum \frac{\sigma(S)}{\pi(S)} = (n^2 + 2n) - \left( 1 + \frac{1}{2} + \frac{1}{3} + \cdots + \frac{1}{n} \right)  (n+1),\] where "$\Sigma$" denotes a sum involving all nonempty subsets $S$ of $\{1,2,3, \ldots,n\}$.

Solution

Problem 3

Show that, for any fixed integer $\,n \geq 1,\,$ the sequence \[2, \; 2^2, \; 2^{2^2}, \; 2^{2^{2^2}}, \ldots  \pmod{n}\] is eventually constant.

[The tower of exponents is defined by $a_1 = 2, \; a_{i+1} = 2^{a_i}$. Also $a_i \pmod{n}$ means the remainder which results from dividing $\,a_i\,$ by $\,n$.]

Solution

Problem 4

Let $\, a =(m^{m+1} + n^{n+1})/(m^m + n^n), \,$ where $\,m\,$ and $\,n\,$ are positive integers. Prove that $\,a^m + a^n \geq m^m + n^n$.

[You may wish to analyze the ratio $\,(a^N - N^N)/(a-N),$ for real $\, a \geq 0 \,$ and integer $\, N \geq 1$.]

Solution

Problem 5

Let $\, D \,$ be an arbitrary point on side $\, AB \,$ of a given triangle $\, ABC, \,$ and let $\, E \,$ be the interior point where $\, CD \,$ intersects the external common tangent to the incircles of triangles $\, ACD \,$ and $\, BCD$. As $\, D \,$ assumes all positions between $\, A \,$ and $\, B \,$, prove that the point $\, E \,$ traces the arc of a circle.

[asy] size(220); defaultpen(1); pair A=(0,0), B=(220,0), C=(18.7723,118.523); pair D=(72.6,0);  pair Ia=incenter(A,D,C), Ib=incenter(B,D,C); pair Ta=(24.9758,52.5775),Tb=(86.6196,67.4129); pair E=IntersectionPoint((Ta--Tb),(C--D)); path Oa=circle(Ia,inradius(A,D,C)); path Ob=circle(Ib,inradius(B,D,C)); pair Da=IP(Oa,A--B), Db=IP(Ob,A--B);  draw(D--C--A--B--C); draw(Ta--Tb); draw(Oa); draw(Ob);  dot(A,linewidth(4)); dot(B,linewidth(4)); dot(C,linewidth(4)); dot(D,linewidth(4)); dot(E,linewidth(4)); dot(Ta,linewidth(4)); dot(Tb,linewidth(4));  label("\(A\)",A,SW); label("\(B\)",B,SE); label("\(C\)",C,W); label("\(D\)",D,S); label("\(E\)",E,NNE); [/asy]

Solution

See Also

1991 USAMO (ProblemsResources)
Preceded by
1990 USAMO
Followed by
1992 USAMO
1 2 3 4 5
All USAMO Problems and Solutions

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