Difference between revisions of "1966 AHSME Problems/Problem 2"
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| + | == Problem == | ||
When the base of a triangle is increased 10% and the altitude to this base is decreased 10%, the change in area is | When the base of a triangle is increased 10% and the altitude to this base is decreased 10%, the change in area is | ||
<math> \text{(A)}\ 1\%~\text{increase}\qquad\text{(B)}\ \frac{1}2\%~\text{increase}\qquad\text{(C)}\ 0\%\qquad\text{(D)}\ \frac{1}2\% ~\text{decrease}\qquad\text{(E)}\ 1\% ~\text{decrease} </math> | <math> \text{(A)}\ 1\%~\text{increase}\qquad\text{(B)}\ \frac{1}2\%~\text{increase}\qquad\text{(C)}\ 0\%\qquad\text{(D)}\ \frac{1}2\% ~\text{decrease}\qquad\text{(E)}\ 1\% ~\text{decrease} </math> | ||
| + | |||
| + | == Solution == | ||
| + | <math>\fbox{E}</math> | ||
| + | |||
| + | == See also == | ||
| + | {{AHSME box|year=1966|num-b=1|num-a=3}} | ||
| + | |||
| + | [[Category:Introductory Geometry Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 01:41, 15 September 2014
Problem
When the base of a triangle is increased 10% and the altitude to this base is decreased 10%, the change in area is
Solution
See also
| 1966 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
