Difference between revisions of "2006 AMC 10B Problems/Problem 13"
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So the desired ratio is: <math> \frac{2}{\frac{12}{7}} = \frac{7}{6} \Rightarrow E </math> | So the desired ratio is: <math> \frac{2}{\frac{12}{7}} = \frac{7}{6} \Rightarrow E </math> | ||
| − | This is problem 6.2.5 in the | + | This is problem 6.2.5 in "the Art of Problem Solving, Introduction to Algebra". |
== See Also == | == See Also == | ||
Revision as of 16:08, 29 December 2013
Problem
Joe and JoAnn each bought 12 ounces of coffee in a 16 ounce cup. Joe drank 2 ounces of his coffee and then added 2 ounces of cream. JoAnn added 2 ounces of cream, stirred the coffee well, and then drank 2 ounces. What is the resulting ratio of the amount of cream in Joe's coffee to that in JoAnn's coffee?
Solution
After drinking and adding cream, Joe's cup has 
ounces of cream.
After adding cream to her cup, JoAnn's cup had 
ounces of liquid. By drinking ounces out of the ounces of liquid, she drank
th of the cream. So there is 
ounces of cream left.
So the desired ratio is: 
This is problem 6.2.5 in "the Art of Problem Solving, Introduction to Algebra".
See Also
| 2006 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 12 |
Followed by Problem 14 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
