Difference between revisions of "1967 AHSME Problems/Problem 3"
(Created page with "== Problem == The side of an equilateral triangle is <math>s</math>. A circle is inscribed in the triangle and a square is inscribed in the circle. The area of the square is: ...") |
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== Solution == | == Solution == | ||
− | <math>\fbox{B}</math> | + | The radius of our circle is <math>\frac{\sqrt{3}}{6}s</math>. This means the square has side length <math>\frac{\sqrt{6}}{6}s</math> which has area of <math>\frac{s^2}{6}=\fbox{B}</math>. |
== See also == | == See also == |
Revision as of 10:07, 29 May 2021
Problem
The side of an equilateral triangle is . A circle is inscribed in the triangle and a square is inscribed in the circle. The area of the square is:
Solution
The radius of our circle is . This means the square has side length which has area of .
See also
1967 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.