Difference between revisions of "2013 AMC 8 Problems/Problem 4"

Revision as of 15:58, 2 November 2020

Problem

Eight friends ate at a restaurant and agreed to share the bill equally. Because Judi forgot her money, each of her seven friends paid an extra $2.50 to cover her portion of the total bill. What was the total bill?

$\textbf{(A)}\ \text{\textdollar}120\qquad\textbf{(B)}\ \text{\textdollar}128\qquad\textbf{(C)}\ \text{\textdollar}140\qquad\textbf{(D)}\ \text{\textdollar}144\qquad\textbf{(E)}\ \text{\textdollar}160$

Solution

2013 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 3	Followed by Problem 5
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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 ==Solution==
-Each of her seven friends paid <math>\text{\textdollar}2.50</math> to cover Judi's portion. Therefore, Judi's portion must be <math>\text{\textdollar}2.50 \cdot 7 = {\textdollar}17.50</math>. Since each friend was supposed to pay the same amount, each friend was supposed to pay <math>\frac{1}{8}</math> of the total bill; the total bill must be <math>8 \cdot 7 \cdot \text{\textdollar}2.50 = \boxed{\textbf{(C)} \ \text{\textdollar}140}</math>.
 ==See Also==
 {{AMC8 box|year=2013|num-b=3|num-a=5}}
 {{MAA Notice}}

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Difference between revisions of "2013 AMC 8 Problems/Problem 4"

Revision as of 15:58, 2 November 2020

Problem

Solution

See Also