Difference between revisions of "2009 AMC 8 Problems/Problem 20"

Revision as of 21:59, 13 November 2016

Problem

How many non-congruent triangles have vertices at three of the eight points in the array shown below?

$[asy]dot((0,0)); dot((5,.5)); dot((.5,0)); dot((.5,.5)); dot((1,0)); dot((1,.5)); dot((1.5,0)); dot((1.5,.5));[/asy]$

$\textbf{(A)}\ 5 \qquad \textbf{(B)}\ 6 \qquad \textbf{(C)}\ 7 \qquad \textbf{(D)}\ 8 \qquad \textbf{(E)}\ 9$

Solution

Assume the base of the triangle is on the bottom four points, because a congruent triangle can be made by reflecting the base on the top four points. For a triangle with a base of length $1$ , there are $3$ triangles. For a triangle with a base of length $2$ , there are $3$ triangles. For length $3$ , there are $2$ . In total, the number of non-congruent triangles is $3+3+2=\boxed{\textbf{(D)}\ 8}$ .

2009 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 19	Followed by Problem 21
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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Difference between revisions of "2009 AMC 8 Problems/Problem 20"

Revision as of 21:59, 13 November 2016

Problem

Solution

See Also

@@ Line 4: / Line 4: @@
 <asy>dot((0,0));
-dot((0,.5));
+dot((5,.5));
 dot((.5,0));
 dot((.5,.5));