Difference between revisions of "2006 AMC 10A Problems/Problem 18"

Revision as of 14:56, 4 August 2006

Problem

A license plate in a certain state consists of 4 digits, not necessarily distinct, and 2 letters, also not necessarily distinct. These six characters may appear in any order, except that the two letters must appear next to each other. How many distinct license plates are possible?

$\mathrm{(A) \ } 10^4\times 26^2\qquad\mathrm{(B) \ } 10^3\times 26^3\qquad\mathrm{(C) \ } 5\times 10^4\times 26^2\qquad\mathrm{(D) \ } 10^2\times 26^4\qquad\mathrm{(E) \ } 5\times 10^3\times 26^3\qquad$

Solution

There are $10\cdot10\cdot10\cdot10 = 10^4$ ways to choose 4 digits.

There are $26 \cdot 26 = 26^2$ ways to choose the 2 letters.

For the letters to be next to each other, they can be the 1st and 2nd, 2nd and 3rd, 3rd and 4th, 4th and 5th, or the 5th and 6th characters. So, there are $5$ choices for position.

Therefore the number of distinct license plates is $5\times 10^4\times 26^2 \Rightarrow C$

@@ Line 11: / Line 11: @@
 So, there are <math>5</math> choices for position.
-Therefore there are  <math> 5\times 10^4\times 26^2 </math> distinct license plates <math> \Rightarrow (C) </math>
+Therefore the number of distinct license plates is  <math> 5\times 10^4\times 26^2 \Rightarrow C </math>
 == See Also ==
 *[[2006 AMC 10A Problems]]
+*[[2006 AMC 10A Problems/Problem 17|Previous Problem]]
+*[[2006 AMC 10A Problems/Problem 19|Next Problem]]
+[[Category:Introductory Combinatorics Problems]]

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Difference between revisions of "2006 AMC 10A Problems/Problem 18"

Revision as of 14:56, 4 August 2006

Problem

Solution

See Also