Difference between revisions of "2016 AMC 8 Problems/Problem 25"

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[Diagram]
 
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<math>\textbf{(A) }4 \sqrt{3}\qquad\textbf{(B) } \Dfrac{120}{17}\qquad\textbf{(C) }10\qquad\textbf{(D) }\Dfrac{17\sqrt{2}}{2}\qquad \textbf{(E) \frac{17\sqrt{3}}{2}</math>
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<math>\textbf{(A) }4 \sqrt{3}\qquad\textbf{(B) } \dfrac{120}{17}\qquad\textbf{(C) }10\qquad\textbf{(D) }\dfrac{17\sqrt{2}}{2}\qquad \textbf{(E)} \dfrac{17\sqrt{3}}{2}</math>
  
 
==Solution==
 
==Solution==

Revision as of 09:39, 23 November 2016

25. A semicircle is inscribed in an isosceles triangle with base $16$ and height $15$ so that the diameter of the semicircle is contained in the base of the triangle as shown. What is the radius of the semicircle?

[Diagram]

$\textbf{(A) }4 \sqrt{3}\qquad\textbf{(B) } \dfrac{120}{17}\qquad\textbf{(C) }10\qquad\textbf{(D) }\dfrac{17\sqrt{2}}{2}\qquad \textbf{(E)} \dfrac{17\sqrt{3}}{2}$

Solution

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2016 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
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All AJHSME/AMC 8 Problems and Solutions

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