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Difference between revisions of "2016 AMC 8 Problems/Problem 14"

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==Solution==
 
==Solution==
  
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Since he uses a gallon of gas every <math>35</math> miles, he had used <math>\frac{350}{35} = 10</math> gallons after <math>350</math> miles. Therefore, after the first leg of his trip he had <math>14 - 10 = 4</math> gallons of gas left. Then, he bought <math>8</math> gallons of gas, which brought him up to <math>12</math> gallons of gas in his gas tank. When he arrived, he had <math>\frac{1}{2} \cdot 14 = 7</math> gallons of gas. So he used <math>5</math> gallons of gas on the second leg of his trip. Therefore, the second part of his trip covered <math>5 \cdot 35 = 175</math> miles. Adding this to the <math>350</math> miles, we see that he drove <math>350 + 175 = \boxed{\textbf{(A)} 525}</math> miles.
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Since he uses a gallon of gas every <math>35</math> miles, he had used <math>\frac{350}{35} = 10</math> gallons after <math>350</math> miles. Therefore, after the first leg of his trip he had <math>14 - 10 = 4</math> gallons of gas left. Then, he bought <math>8</math> gallons of gas, which brought him up to <math>12</math> gallons of gas in his gas tank. When he arrived, he had <math>\frac{1}{2} \cdot 14 = 7</math> gallons of gas. So he used <math>5</math> gallons of gas on the second leg of his trip. Therefore, the second part of his trip covered <math>5 \cdot 35 = 175</math> miles. Adding this to the <math>350</math> miles, we see that he drove <math>350 + 175 = \boxed{\textbf{(A)}   \, 525}</math> miles.
  
 
{{AMC8 box|year=2016|num-b=13|num-a=15}}
 
{{AMC8 box|year=2016|num-b=13|num-a=15}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 13:07, 23 November 2016

Karl's car uses a gallon of gas every $35$ miles, and his gas tank holds $14$ gallons when it is full. One day, Karl started with a full tank of gas, drove $350$ miles, bought $8$ gallons of gas, and continued driving to his destination. When he arrived, his gas tank was half full. How many miles did Karl drive that day?

$\textbf{(A)}\mbox{ }525\qquad\textbf{(B)}\mbox{ }560\qquad\textbf{(C)}\mbox{ }595\qquad\textbf{(D)}\mbox{ }665\qquad\textbf{(E)}\mbox{ }735$

Solution

Since he uses a gallon of gas every $35$ miles, he had used $\frac{350}{35} = 10$ gallons after $350$ miles. Therefore, after the first leg of his trip he had $14 - 10 = 4$ gallons of gas left. Then, he bought $8$ gallons of gas, which brought him up to $12$ gallons of gas in his gas tank. When he arrived, he had $\frac{1}{2} \cdot 14 = 7$ gallons of gas. So he used $5$ gallons of gas on the second leg of his trip. Therefore, the second part of his trip covered $5 \cdot 35 = 175$ miles. Adding this to the $350$ miles, we see that he drove $350 + 175 = \boxed{\textbf{(A)} \, 525}$ miles.

2016 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 13 		Followed by
Problem 15
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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