Difference between revisions of "2009 AMC 8 Problems/Problem 12"
Evanyou123 (talk | contribs) (→Solution) |
Evanyou123 (talk | contribs) (→Solution) |
||
Line 32: | Line 32: | ||
\end{tabular}</cmath> | \end{tabular}</cmath> | ||
− | Only <math>9</math> | + | Only <math>9</math> is not prime, so there are <math>7</math> prime numbers and <math>9</math> total numbers for a probability of <math>\boxed{\textbf{(D)}\ \frac79}</math>. |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2009|num-b=11|num-a=13}} | {{AMC8 box|year=2009|num-b=11|num-a=13}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 08:15, 28 October 2017
Problem
The two spinners shown are spun once and each lands on one of the numbered sectors. What is the probability that the sum of the numbers in the two sectors is prime?
Solution
The possible sums are
Only is not prime, so there are prime numbers and total numbers for a probability of .
See Also
2009 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.