Difference between revisions of "2006 AMC 10B Problems/Problem 22"
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Setting this equal to <math>253</math>¢: | Setting this equal to <math>253</math>¢: | ||
− | <math>N(4B+5J)=253=11\ | + | <math>N(4B+5J)=253=11\cdot23</math> |
The only possible positive integer pairs <math>(N , 4B+5J)</math> whose product is <math>253</math> are: <math> (1,253) ; (11,23) ; (23,11) ; (253,1) </math> | The only possible positive integer pairs <math>(N , 4B+5J)</math> whose product is <math>253</math> are: <math> (1,253) ; (11,23) ; (23,11) ; (253,1) </math> | ||
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The only integer solutions for <math>B</math> and <math>J</math> are <math>B=2</math> and <math>J=3</math> | The only integer solutions for <math>B</math> and <math>J</math> are <math>B=2</math> and <math>J=3</math> | ||
− | Therefore the cost of the jam Elmo uses to make the sandwiches is <math>3\cdot5\cdot11=165</math>¢ <math> = | + | Therefore the cost of the jam Elmo uses to make the sandwiches is <math>3\cdot5\cdot11=165</math>¢ <math> = </math>1.65 \Rightarrow D $ |
== See Also == | == See Also == |
Revision as of 16:42, 11 May 2008
Problem
Elmo makes sandwiches for a fundraiser. For each sandwich he uses globs of peanut butter at ¢ per glob and blobs of jam at ¢ per blob. The cost of the peanut butter and jam to make all the sandwiches is . Assume that , , and are positive integers with . What is the cost of the jam Elmo uses to make the sandwiches?
Solution
The peanut butter and jam for each sandwich costs ¢, so the peanut butter and jam for sandwiches costs ¢.
Setting this equal to ¢:
The only possible positive integer pairs whose product is are:
The first pair violates and the third and fourth pair have no positive integer solutions for and .
So, and
The only integer solutions for and are and
Therefore the cost of the jam Elmo uses to make the sandwiches is ¢ 1.65 \Rightarrow D $