Difference between revisions of "2019 AMC 12A Problems/Problem 2"

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==Solution==
 
==Solution==
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<math>a=1.5b</math>
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Therfore,
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<math>b=a/1.5</math>
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<math>3b=2a</math>
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<math>2a</math> is <math>\boxed{200%}</math> of <math>a</math>.
  
 
==See Also==
 
==See Also==

Revision as of 17:09, 9 February 2019

Problem

Suppose $a$ is $150\%$ of $b$. What percent of $a$ is $3b$?

$\textbf{(A) } 50 \qquad \textbf{(B) } 66\frac{2}{3} \qquad \textbf{(C) } 150 \qquad \textbf{(D) } 200 \qquad \textbf{(E) } 450$

Solution

$a=1.5b$ Therfore, $b=a/1.5$ $3b=2a$ $2a$ is $\boxed{200%}$ (Error compiling LaTeX. Unknown error_msg) of $a$.

See Also

2019 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
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All AMC 12 Problems and Solutions

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