Difference between revisions of "2019 AMC 12A Problems/Problem 2"

Revision as of 17:10, 9 February 2019

Suppose $a$ is $150\%$ of $b$ . What percent of $a$ is $3b$ ?

$\textbf{(A) } 50 \qquad \textbf{(B) } 66\frac{2}{3} \qquad \textbf{(C) } 150 \qquad \textbf{(D) } 200 \qquad \textbf{(E) } 450$

$a=1.5b$ Therfore, $b=a/1.5$ $3b=2a$ $2a$ is $\boxed{200}$ of $a$ .

2019 AMC 12A (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 3
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All AMC 12 Problems and Solutions

@@ Line 10: / Line 10: @@
 <math>b=a/1.5</math>
 <math>3b=2a</math>
-<math>2a</math> is <math>\boxed{200%}</math> of <math>a</math>.
+<math>2a</math> is <math>\boxed{200}</math> of <math>a</math>.
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