Difference between revisions of "2006 Cyprus Seniors Provincial/2nd grade/Problem 2"

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== Problem ==
 
== Problem ==
Lte <math>\Alpha, \Beta, \Gamma</math> be consecutive points on a straight line <math>(\epsilon)</math>. We construct equilateral triangles <math>\Alpha\Beta\Delta</math> and <math>\Beta\Gamma\Epsilon</math> to the same side of <math>(\epsilon)</math>.
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Let <math>\Alpha, \Beta, \Gamma</math> be consecutive points on a straight line <math>(\epsilon)</math>. We construct equilateral triangles <math>\Alpha\Beta\Delta</math> and <math>\Beta\Gamma\Epsilon</math> to the same side of <math>(\epsilon)</math>.
  
 
a) Prove that <math>\angle\Alpha\Epsilon\Beta = \angle\Delta\Gamma\Beta</math>
 
a) Prove that <math>\angle\Alpha\Epsilon\Beta = \angle\Delta\Gamma\Beta</math>

Revision as of 10:33, 11 November 2006

Problem

Let $\Alpha, \Beta, \Gamma$ (Error compiling LaTeX. Unknown error_msg) be consecutive points on a straight line $(\epsilon)$. We construct equilateral triangles $\Alpha\Beta\Delta$ (Error compiling LaTeX. Unknown error_msg) and $\Beta\Gamma\Epsilon$ (Error compiling LaTeX. Unknown error_msg) to the same side of $(\epsilon)$.

a) Prove that $\angle\Alpha\Epsilon\Beta = \angle\Delta\Gamma\Beta$ (Error compiling LaTeX. Unknown error_msg)

b) If $x_{1}$ is the distance of $A$ form $\Gamma\Delta$ and $x_{2}$ is the distance of $\Gamma$ form $\Alpha\Gamma$ (Error compiling LaTeX. Unknown error_msg) prove that

$\frac{x_{1}}{x_{2}} = \frac{Area(\Alpha\Gamma\Delta)}{Area(\Alpha\Gamma\Epsilon)} = \frac{\Alpha\Beta}{\Beta\Gamma}$ (Error compiling LaTeX. Unknown error_msg)


Solution


See also