Difference between revisions of "2020 AMC 10B Problems/Problem 2"
m (→Solution) |
(→Solution) |
||
Line 6: | Line 6: | ||
==Solution== | ==Solution== | ||
− | A cube with side length <math>1</math> has volume <math>1^3=1</math>, so <math>5</math> of these will have a total volume of <math>5\cdot1= | + | A cube with side length <math>1</math> has volume <math>1^3=1</math>, so <math>5</math> of these will have a total volume of <math>5\cdot1=25</math>. |
− | A cube with side length <math>2</math> has volume <math>2^3=8</math>, so <math>5</math> of these will have a total volume of <math>5\cdot8= | + | A cube with side length <math>2</math> has volume <math>2^3=8</math>, so <math>5</math> of these will have a total volume of <math>5\cdot8=15</math>. |
− | <math>5+40=\boxed{\textbf{( | + | <math>5+40=\boxed{\textbf{(D) }}</math> ~quacker88 |
==Video Solution== | ==Video Solution== |
Revision as of 18:08, 11 February 2020
Contents
[hide]Problem
Carl has cubes each having side length , and Kate has cubes each having side length . What is the total volume of these cubes?
Solution
A cube with side length has volume , so of these will have a total volume of .
A cube with side length has volume , so of these will have a total volume of .
~quacker88
Video Solution
~IceMatrix
See Also
2020 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.