Difference between revisions of "1993 AHSME Problems/Problem 5"

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== Solution ==
 
== Solution ==
Since the bicycle originally cost <math>160, the new cost will be 160 * 5% = 160 * 1/20 = 8, and 160 + 8 = 168. The new cost of the helmet will be 40 * 10% = 40 * 1/10 = 4, and 40 + 4 = 44. 160 + 40 = 200, and 168 + 44 = 212, so the total percent increase is 12/200 = 6% </math>\fbox A$
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Since the bicycle originally cost $160, the new cost will be 160 * 5% = 160 * 1/20 = 8, and 160 + 8 = 168. The new cost of the helmet will be 40 * 10% = 40 * 1/10 = 4, and 40 + 4 = 44. 160 + 40 = 200, and 168 + 44 = 212, so the total percent increase is 12/200 = 6%, or A.
  
 
== See also ==
 
== See also ==

Latest revision as of 23:24, 16 February 2020

Problem

Last year a bicycle cost $160 and a cycling helmet $40. This year the cost of the bicycle increased by $5\%$, and the cost of the helmet increased by $10\%$. The percent increase in the combined cost of the bicycle and the helmet is:

$\text{(A) } 6\%\quad \text{(B) } 7\%\quad \text{(C) } 7.5\%\quad \text{(D) } 8\%\quad \text{(E) } 15\%$

Solution

Since the bicycle originally cost $160, the new cost will be 160 * 5% = 160 * 1/20 = 8, and 160 + 8 = 168. The new cost of the helmet will be 40 * 10% = 40 * 1/10 = 4, and 40 + 4 = 44. 160 + 40 = 200, and 168 + 44 = 212, so the total percent increase is 12/200 = 6%, or A.

See also

1993 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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