Difference between revisions of "2015 AMC 10B Problems/Problem 1"
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==Solution== | ==Solution== | ||
<math>2-(-2)^{-2}=2-\frac{1}{(-2)^2}=2-\frac{1}{4}=\frac{8}{4}-\frac{1}{4}=\boxed{\textbf{(C) }\frac{7}{4}}</math> | <math>2-(-2)^{-2}=2-\frac{1}{(-2)^2}=2-\frac{1}{4}=\frac{8}{4}-\frac{1}{4}=\boxed{\textbf{(C) }\frac{7}{4}}</math> | ||
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| + | ==Video Solution== | ||
| + | https://youtu.be/0j5_-SaZdJ8 | ||
| + | |||
| + | ~savannahsolver | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2015|ab=B|before=First Problem|num-a=2}} | {{AMC10 box|year=2015|ab=B|before=First Problem|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 17:03, 16 June 2020
Contents
Problem
What is the value of 
?
Solution
Video Solution
~savannahsolver
See Also
| 2015 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
