Difference between revisions of "2015 AMC 10B Problems/Problem 5"
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==Solution== | ==Solution== | ||
Because Marta was <math>6</math>th, Jack was <math>5</math>th, so Todd was <math>3</math>rd. Thus, Rand was <math>2</math>nd and the 8th place finisher was <math>\boxed{\mathbf{(B)}\ \mathrm{Hikmet}}</math> | Because Marta was <math>6</math>th, Jack was <math>5</math>th, so Todd was <math>3</math>rd. Thus, Rand was <math>2</math>nd and the 8th place finisher was <math>\boxed{\mathbf{(B)}\ \mathrm{Hikmet}}</math> | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/61oSoeT0ULA | ||
+ | |||
+ | ~savannahsolver | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2015|ab=B|num-b=4|num-a=6}} | {{AMC10 box|year=2015|ab=B|num-b=4|num-a=6}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 14:07, 25 June 2020
Contents
Problem
David, Hikmet, Jack, Marta, Rand, and Todd were in a -person race with
other people. Rand finished
places ahead of Hikmet. Marta finished
place behind Jack. David finished
places behind Hikmet. Jack finished
places behind Todd. Todd finished
place behind Rand. Marta finished in
th place. Who finished in
th place?
Solution
Because Marta was th, Jack was
th, so Todd was
rd. Thus, Rand was
nd and the 8th place finisher was
Video Solution
~savannahsolver
See Also
2015 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.