Difference between revisions of "1988 AJHSME Problems/Problem 6"
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We expand <math>\frac{(0.2)^3}{(0.02)^2}</math>, and get <math>\frac{(0.2)*(0.2)*(0.2)}{(0.02)(0.02)}</math>. The two <math>0.02</math>'s "cancel" out with the two <math>0.2</math>'s, leaving the fraction as: <math>(10)*(10)*(0.2)</math>. Using basic calculations, we compute this expression to get <math>20\Rightarrow \mathrm{(E)}</math>. | We expand <math>\frac{(0.2)^3}{(0.02)^2}</math>, and get <math>\frac{(0.2)*(0.2)*(0.2)}{(0.02)(0.02)}</math>. The two <math>0.02</math>'s "cancel" out with the two <math>0.2</math>'s, leaving the fraction as: <math>(10)*(10)*(0.2)</math>. Using basic calculations, we compute this expression to get <math>20\Rightarrow \mathrm{(E)}</math>. | ||
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+ | ~sakshamsethi | ||
==See Also== | ==See Also== |
Revision as of 22:16, 8 July 2020
Contents
Problem
Solution
Converting the decimals to fractions gives us .
Solution 2
We expand , and get . The two 's "cancel" out with the two 's, leaving the fraction as: . Using basic calculations, we compute this expression to get .
~sakshamsethi
See Also
1988 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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