Difference between revisions of "1989 AIME Problems/Problem 6"

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== Problem ==
 
== Problem ==
Two skaters, Allie and Billie, are at points <math>A^{}_{}</math> and <math>B^{}_{}</math>, respectively, on a flat, frozen lake. The distance between <math>A^{}_{}</math> and <math>B^{}_{}</math> is <math>100^{}_{}</math> meters. Allie leaves <math>A^{}_{}</math> and skates at a speed of <math>8^{}_{}</math> meters per second on a straight line that makes a <math>60^\circ</math> angle with <math>AB^{}_{}</math>. At the same time Allie leaves <math>A^{}_{}</math>, Billie leaves <math>B^{}_{}</math> at a speed of <math>7^{}_{}</math> meters per second and follows the straight path that produces the earliest possible meeting of the two skaters, given their speeds. How many meters does Allie skate before meeting Billie?
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Two skaters, Allie and Billie, are at [[point]]s <math>A^{}_{}</math> and <math>B^{}_{}</math>, respectively, on a flat, frozen lake. The [[distance]] between <math>A^{}_{}</math> and <math>B^{}_{}</math> is <math>100^{}_{}</math> meters. Allie leaves <math>A^{}_{}</math> and skates at a [[speed]] of <math>8^{}_{}</math> meters per second on a straight line that makes a <math>60^\circ</math> angle with <math>AB^{}_{}</math>. At the same time Allie leaves <math>A^{}_{}</math>, Billie leaves <math>B^{}_{}</math> at a speed of <math>7^{}_{}</math> meters per second and follows the [[straight]] path that produces the earliest possible meeting of the two skaters, given their speeds. How many meters does Allie skate before meeting Billie?
  
 
[[Image:AIME_1989_Problem_6.png]]
 
[[Image:AIME_1989_Problem_6.png]]
  
 
== Solution ==
 
== Solution ==
{{solution}}
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Label the point of [[intersection]] as <math>C</math>. Since <math>d = rt</math>, <math>AC = 8t</math> and <math>BC = 7t</math>. According to the [[law of cosines]],
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:<math>(7t)^2 = (8t)^2 + 100^2 - 2 \cdot 8t \cdot 100 \cdot \cos 60</math>
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:<math>0 = 15t^2 - 800t + 10000 = 3t^2 - 160t + 2000</math>
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:<math>t = \frac{160 \pm \sqrt{160^2 - 4\cdot 3 \cdot 2000}}{6} = 20, \frac{100}{3}</math>.
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Since we are looking for the earliest possible intersection, <math>20</math> seconds are needed. Thus, <math>8 \cdot 20 = 160</math> meters is the solution.
  
 
== See also ==
 
== See also ==
* [[1989 AIME Problems/Problem 7|Next Problem]]
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{{AIME box|year=1989|num-b=5|num-a=7}}
* [[1989 AIME Problems/Problem 5|Previous Problem]]
 
* [[1989 AIME Problems]]
 

Revision as of 20:45, 26 February 2007

Problem

Two skaters, Allie and Billie, are at points $A^{}_{}$ and $B^{}_{}$, respectively, on a flat, frozen lake. The distance between $A^{}_{}$ and $B^{}_{}$ is $100^{}_{}$ meters. Allie leaves $A^{}_{}$ and skates at a speed of $8^{}_{}$ meters per second on a straight line that makes a $60^\circ$ angle with $AB^{}_{}$. At the same time Allie leaves $A^{}_{}$, Billie leaves $B^{}_{}$ at a speed of $7^{}_{}$ meters per second and follows the straight path that produces the earliest possible meeting of the two skaters, given their speeds. How many meters does Allie skate before meeting Billie?

AIME 1989 Problem 6.png

Solution

Label the point of intersection as $C$. Since $d = rt$, $AC = 8t$ and $BC = 7t$. According to the law of cosines,

$(7t)^2 = (8t)^2 + 100^2 - 2 \cdot 8t \cdot 100 \cdot \cos 60$
$0 = 15t^2 - 800t + 10000 = 3t^2 - 160t + 2000$
$t = \frac{160 \pm \sqrt{160^2 - 4\cdot 3 \cdot 2000}}{6} = 20, \frac{100}{3}$.

Since we are looking for the earliest possible intersection, $20$ seconds are needed. Thus, $8 \cdot 20 = 160$ meters is the solution.

See also

1989 AIME (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
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All AIME Problems and Solutions