Difference between revisions of "1997 AIME Problems/Problem 14"
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<math>\displaystyle z=e^{\frac{2\pi ik}{1997}}</math> | <math>\displaystyle z=e^{\frac{2\pi ik}{1997}}</math> | ||
− | <math>\displaystyle z=\cos(\frac{2\pi k}{1997})+i\sin(\frac{2\pi k}{1997})</math> | + | <math>\displaystyle z=\cos\left(\frac{2\pi k}{1997}\right)+i\sin\left(\frac{2\pi k}{1997}\right)</math> |
− | Now, let <math>\displaystyle v</math> be the root corresponding to <math>\displaystyle \theta=\frac{2\pi m}{1997}</math>, and let <math>\displaystyle w</math> be the root corresponding to <math>\displaystyle \theta=\frac{2\pi n}{1997}</math> | + | Now, let <math>\displaystyle v</math> be the root corresponding to <math>\displaystyle \theta=\frac{2\pi m}{1997}</math>, and let <math>\displaystyle w</math> be the root corresponding to <math>\displaystyle \theta=\frac{2\pi n}{1997}</math>. The magnitude of <math>\displaystyle v+w</math> is therefore: |
== See also == | == See also == | ||
* [[1997 AIME Problems]] | * [[1997 AIME Problems]] |
Revision as of 19:19, 7 March 2007
Problem
Let and be distinct, randomly chosen roots of the equation . Let be the probability that , where and are relatively prime positive integers. Find .
Solution
The solution requires the use of Euler's formula:
If , where k is any constant, the equation reduces to:
Now, substitute this into the equation:
Now, let be the root corresponding to , and let be the root corresponding to . The magnitude of is therefore: