Difference between revisions of "2020 AMC 8 Problems/Problem 12"
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==Video Solution== | ==Video Solution== | ||
− | https://youtu.be/ | + | https://youtu.be/63BRTfp-ESM |
==See also== | ==See also== | ||
{{AMC8 box|year=2020|num-b=11|num-a=13}} | {{AMC8 box|year=2020|num-b=11|num-a=13}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 23:49, 27 November 2020
Contents
[hide]Problem
For a positive integer , the factorial notation
represents the product of the integers from
to
. (For example,
.) What value of
satisfies the following equation?
Solution 1
We have , and
. Therefore the equation becomes
, and so
. Cancelling the
s, it is clear that
.
Solution 2 (variant of Solution 1)
Since , we obtain
, which becomes
and thus
. We therefore deduce
.
Solution 3 (using answer choices)
We can see that the answers to
contain a factor of
, but there is no such factor of
in
. Therefore, the answer must be
.
Video Solution
See also
2020 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.