Difference between revisions of "2021 AMC 10A Problems/Problem 3"
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These problems will not be released until the 2021 AMC 10A is released. | These problems will not be released until the 2021 AMC 10A is released. | ||
==Solution== | ==Solution== | ||
| − | We don't know yet. | + | We don't know yet, but since 10+9=21, we know that the answer is G. |
| + | |||
==Note== | ==Note== | ||
This problem might also be on the AMC 12A. If so, please redirect it there. | This problem might also be on the AMC 12A. If so, please redirect it there. | ||
Revision as of 14:02, 6 January 2021
Contents
Problem
These problems will not be released until the 2021 AMC 10A is released.
Solution
We don't know yet, but since 10+9=21, we know that the answer is G.
Note
This problem might also be on the AMC 12A. If so, please redirect it there.
See also
| 2021 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
