Difference between revisions of "2016 AMC 8 Problems/Problem 1"

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== Problem ==
 
The longest professional tennis match ever played lasted a total of <math>11</math> hours and <math>5</math> minutes. How many minutes was this?
 
The longest professional tennis match ever played lasted a total of <math>11</math> hours and <math>5</math> minutes. How many minutes was this?
  
 
<math>\textbf{(A) }605\qquad\textbf{(B) }655\qquad\textbf{(C) }665\qquad\textbf{(D) }1005\qquad \textbf{(E) }1105</math>
 
<math>\textbf{(A) }605\qquad\textbf{(B) }655\qquad\textbf{(C) }665\qquad\textbf{(D) }1005\qquad \textbf{(E) }1105</math>
  
==Solution==
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== Solutions ==
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===Solution 1===
 
It is best to split 11 hours and 5 minutes into 2 parts, one of 11 hours and another of 5 minutes.  We know that there is <math>60</math> minutes in a hour.  Therefore, there are <math>11 \cdot 60 = 660</math> minutes in 11 hours.  Adding the second part(the 5 minutes) we get <math>660 + 5 = \boxed{\textbf{(C)}\ 665}</math>.
 
It is best to split 11 hours and 5 minutes into 2 parts, one of 11 hours and another of 5 minutes.  We know that there is <math>60</math> minutes in a hour.  Therefore, there are <math>11 \cdot 60 = 660</math> minutes in 11 hours.  Adding the second part(the 5 minutes) we get <math>660 + 5 = \boxed{\textbf{(C)}\ 665}</math>.
  
==Solution 2==
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===Solution 2===
 
The best method comes when you remember your multiplication tables. Thus trivial, we get our answer of <math>\boxed{{(C) }   
 
The best method comes when you remember your multiplication tables. Thus trivial, we get our answer of <math>\boxed{{(C) }   
 
  665}</math>.
 
  665}</math>.
  
==Solution 3==
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===Solution 3===
 
11 hours 5 min = (11 * 60) + 5 min  = 665 min, therefore  
 
11 hours 5 min = (11 * 60) + 5 min  = 665 min, therefore  
 
<math>\boxed{{(C) }   
 
<math>\boxed{{(C) }   

Revision as of 02:50, 16 January 2021

Problem

The longest professional tennis match ever played lasted a total of $11$ hours and $5$ minutes. How many minutes was this?

$\textbf{(A) }605\qquad\textbf{(B) }655\qquad\textbf{(C) }665\qquad\textbf{(D) }1005\qquad \textbf{(E) }1105$

Solutions

Solution 1

It is best to split 11 hours and 5 minutes into 2 parts, one of 11 hours and another of 5 minutes. We know that there is $60$ minutes in a hour. Therefore, there are $11 \cdot 60 = 660$ minutes in 11 hours. Adding the second part(the 5 minutes) we get $660 + 5 = \boxed{\textbf{(C)}\ 665}$.

Solution 2

The best method comes when you remember your multiplication tables. Thus trivial, we get our answer of $\boxed{{(C) }    665}$.

Solution 3

11 hours 5 min = (11 * 60) + 5 min = 665 min, therefore $\boxed{{(C) }   }$.

Carmen

Video Solution

https://www.youtube.com/watch?v=LqnQQcUVJmA (has questions 1-5)


2016 AMC 8 (ProblemsAnswer KeyResources)
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First Problem
Followed by
Problem 2
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All AJHSME/AMC 8 Problems and Solutions

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