Difference between revisions of "2009 AMC 8 Problems/Problem 6"
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==Solution== | ==Solution== | ||
Each of the four hoses hose fills <math>24,000/4 = 6,000</math> gallons of water. At the rate it goes at it will take <math>6,000/2.5 = 2400</math> minutes, or <math>\boxed{\textbf{(A)}\ 40}</math> hours. | Each of the four hoses hose fills <math>24,000/4 = 6,000</math> gallons of water. At the rate it goes at it will take <math>6,000/2.5 = 2400</math> minutes, or <math>\boxed{\textbf{(A)}\ 40}</math> hours. | ||
| + | |||
| + | ==Video Solution== | ||
| + | https://youtu.be/USVVURBLaAc?t=288 | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2009|num-b=5|num-a=7}} | {{AMC8 box|year=2009|num-b=5|num-a=7}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 22:56, 28 January 2021
Contents
Problem 6
Steve's empty swimming pool will hold 
gallons of water when full. It will be filled by 
hoses, each of which supplies 
gallons of water per minute. How many hours will it take to fill Steve's pool?
Solution
Each of the four hoses hose fills 
gallons of water. At the rate it goes at it will take 
minutes, or 
hours.
Video Solution
https://youtu.be/USVVURBLaAc?t=288
See Also
| 2009 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
