Difference between revisions of "2021 AMC 10A Problems/Problem 1"

Revision as of 14:18, 11 February 2021

What is the value of $(2^2-2)-(3^2-3)+(4^2-4)$

$\textbf{(A) } 1 \qquad\textbf{(B) } 2 \qquad\textbf{(C) } 5 \qquad\textbf{(D) } 8 \qquad\textbf{(E) } 12$

$(4-2)-(9-3)+(16-4)=2-6+12=8.$ This corresponds to $\boxed{\text{D}}$

-happykeeper

2021 AMC 10A (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 10 Problems and Solutions

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 -happykeeper
+==See also==
+{{AMC10 box|year=2021|ab=A|num-b=2|num-a=4}}
+{{MAA Notice}}