Difference between revisions of "2021 AMC 10A Problems/Problem 1"

(Video Solution)
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-happykeeper
 
-happykeeper
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== Solution 2==
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<cmath>\begin{align*}
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(2^2-2)-(3^2-3)+(4^2-4) &= 2(2-1)-3(3-1)+4(4-1) \\
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&= 2(1)-3(2)+4(3) \\
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&= 2-6+12 \\
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&= \boxed{\textbf{(D) } 8}.
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\end{align*}</cmath>
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~MRENTHUSIASM
  
 
== Video Solution (Arithmetic Computation) ==
 
== Video Solution (Arithmetic Computation) ==

Revision as of 03:10, 12 February 2021

Problem

What is the value of \[(2^2-2)-(3^2-3)+(4^2-4)\]

$\textbf{(A) } 1 \qquad\textbf{(B) } 2 \qquad\textbf{(C) } 5 \qquad\textbf{(D) } 8 \qquad\textbf{(E) } 12$

Solution

$(4-2)-(9-3)+(16-4)=2-6+12=8.$ This corresponds to $\boxed{\text{D}}$

-happykeeper

Solution 2

\begin{align*} (2^2-2)-(3^2-3)+(4^2-4) &= 2(2-1)-3(3-1)+4(4-1) \\ &= 2(1)-3(2)+4(3) \\ &= 2-6+12 \\ &= \boxed{\textbf{(D) } 8}. \end{align*} ~MRENTHUSIASM

Video Solution (Arithmetic Computation)

https://youtu.be/0VvM_f-IDvE

~ pi_is_3.14

See Also

2021 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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