Difference between revisions of "2021 JMPSC Accuracy Problems/Problem 1"
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The factors of <math>27</math> are <math>1</math>, <math>3</math>, <math>9</math> and <math>27</math>. Out of these, only <math>3</math>, <math>9</math> and <math>27</math> are multiples of <math>3</math>, so the answer is <math>3 + 9 + 27 = \boxed{39}</math>. | The factors of <math>27</math> are <math>1</math>, <math>3</math>, <math>9</math> and <math>27</math>. Out of these, only <math>3</math>, <math>9</math> and <math>27</math> are multiples of <math>3</math>, so the answer is <math>3 + 9 + 27 = \boxed{39}</math>. | ||
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==See also== | ==See also== |
Latest revision as of 16:22, 11 July 2021
Contents
[hide]Problem
Find the sum of all positive multiples of that are factors of
Solution
We use the fact that and to conclude that the only multiples of that are factors of are , , and . Thus, our answer is .
~Bradygho
Solution 2
The factors of are , , and . Out of these, only , and are multiples of , so the answer is .
~Mathdreams
See also
The problems on this page are copyrighted by the Junior Mathematicians' Problem Solving Competition.