Difference between revisions of "2015 AMC 8 Problems/Problem 1"
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===Solution 2=== | ===Solution 2=== | ||
Since there are <math>3</math> feet in a yard, we divide <math>9</math> by <math>3</math> to get <math>3</math>, and <math>12</math> by <math>3</math> to get <math>4</math>. To find the area of the carpet, we then multiply these two values together to get <math>\boxed{\textbf{(A)}~12}</math>. | Since there are <math>3</math> feet in a yard, we divide <math>9</math> by <math>3</math> to get <math>3</math>, and <math>12</math> by <math>3</math> to get <math>4</math>. To find the area of the carpet, we then multiply these two values together to get <math>\boxed{\textbf{(A)}~12}</math>. | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/758_W_eK81g | ||
+ | |||
+ | ~savannahsolver | ||
==See Also== | ==See Also== |
Revision as of 09:55, 26 March 2022
Problem
Onkon wants to cover his rooms floor with his Favourite red carpet. How many square yards of red carpet are required to cover a rectangular floor that is feet long and
feet wide? (There are 3 feet in a yard.)
Solutions
Solution 1
First, we multiply . To get that you need
square feet of carpet you need to cover. Since there are
square feet in a square yard, you divide
by
to get
square yards, so our answer is
.
Solution 2
Since there are feet in a yard, we divide
by
to get
, and
by
to get
. To find the area of the carpet, we then multiply these two values together to get
.
Video Solution
~savannahsolver
See Also
2015 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.
Placement:Easy Geometry