Difference between revisions of "2015 AMC 10B Problems/Problem 5"
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==Solution== | ==Solution== | ||
Because Marta was <math>6</math>th, Jack was <math>5</math>th, so Todd was <math>3</math>rd. Thus, Rand was <math>2</math>nd and the 8th place finisher was <math>\boxed{\mathbf{(B)}\ \mathrm{Hikmet}}</math> | Because Marta was <math>6</math>th, Jack was <math>5</math>th, so Todd was <math>3</math>rd. Thus, Rand was <math>2</math>nd and the 8th place finisher was <math>\boxed{\mathbf{(B)}\ \mathrm{Hikmet}}</math> | ||
| + | |||
| + | ==Video Solution 1== | ||
| + | https://youtu.be/sNdfksIblfs | ||
| + | |||
| + | ~Education, the Study of Everything | ||
==Video Solution== | ==Video Solution== | ||
Revision as of 17:10, 2 August 2022
Note
NOTE: this problem is supposedly the same as this question: https://artofproblemsolving.com/wiki/index.php/2015_AMC_12B_Problems/Problem_4 but somehow the names are all different
Problem
David, Hikmet, Jack, Marta, Rand, and Todd were in a 
-person race with 
other people. Rand finished places ahead of Hikmet. Marta finished 
place behind Jack. David finished 
places behind Hikmet. Jack finished places behind Todd. Todd finished place behind Rand. Marta finished in th place. Who finished in 
th place?
Solution
Because Marta was th, Jack was 
th, so Todd was 
rd. Thus, Rand was nd and the 8th place finisher was 
Video Solution 1
~Education, the Study of Everything
Video Solution
~savannahsolver
See Also
| 2015 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
