Difference between revisions of "2015 AMC 10B Problems/Problem 5"
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==Problem== | ==Problem== | ||
David, Hikmet, Jack, Marta, Rand, and Todd were in a <math>12</math>-person race with <math>6</math> other people. Rand finished <math>6</math> places ahead of Hikmet. Marta finished <math>1</math> place behind Jack. David finished <math>2</math> places behind Hikmet. Jack finished <math>2</math> places behind Todd. Todd finished <math>1</math> place behind Rand. Marta finished in <math>6</math>th place. Who finished in <math>8</math>th place? | David, Hikmet, Jack, Marta, Rand, and Todd were in a <math>12</math>-person race with <math>6</math> other people. Rand finished <math>6</math> places ahead of Hikmet. Marta finished <math>1</math> place behind Jack. David finished <math>2</math> places behind Hikmet. Jack finished <math>2</math> places behind Todd. Todd finished <math>1</math> place behind Rand. Marta finished in <math>6</math>th place. Who finished in <math>8</math>th place? | ||
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~savannahsolver | ~savannahsolver | ||
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+ | ==Note== | ||
+ | NOTE: this problem is supposedly the same as this question: https://artofproblemsolving.com/wiki/index.php/2015_AMC_12B_Problems/Problem_4 | ||
+ | but somehow the names are all different | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2015|ab=B|num-b=4|num-a=6}} | {{AMC10 box|year=2015|ab=B|num-b=4|num-a=6}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 01:02, 31 August 2022
Problem
David, Hikmet, Jack, Marta, Rand, and Todd were in a -person race with
other people. Rand finished
places ahead of Hikmet. Marta finished
place behind Jack. David finished
places behind Hikmet. Jack finished
places behind Todd. Todd finished
place behind Rand. Marta finished in
th place. Who finished in
th place?
Solution
Because Marta was th, Jack was
th, so Todd was
rd. Thus, Rand was
nd and the 8th place finisher was
Video Solution 1
~Education, the Study of Everything
Video Solution
~savannahsolver
Note
NOTE: this problem is supposedly the same as this question: https://artofproblemsolving.com/wiki/index.php/2015_AMC_12B_Problems/Problem_4 but somehow the names are all different
See Also
2015 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.