Difference between revisions of "2022 AMC 10B Problems/Problem 2"
Ehuang0531 (talk | contribs) (restored original not-to-scale figure in problem statement and moved to-scale figure to solution; ce) |
Ehuang0531 (talk | contribs) (add endmatter) |
||
Line 39: | Line 39: | ||
(Figure redrawn to scale.) | (Figure redrawn to scale.) | ||
− | <math>AD = AP + PD = 3 + 2 = 5 | + | <math>AD = AP + PD = 3 + 2 = 5</math>. |
<math>ABCD</math> is a rhombus, so <math>AB = AP = 5</math>. | <math>ABCD</math> is a rhombus, so <math>AB = AP = 5</math>. | ||
Line 45: | Line 45: | ||
<math>\bigtriangleup APB</math> is a 3-4-5 right triangle, so <math>BP = 4</math>. | <math>\bigtriangleup APB</math> is a 3-4-5 right triangle, so <math>BP = 4</math>. | ||
− | The area of the rhombus <math>= bh = (AD)(BP) = 5 | + | The area of the rhombus <math>= bh = (AD)(BP) = 5 \cdot 4 = \boxed{\textbf{(D) }20}</math>. |
~richiedelgado | ~richiedelgado | ||
+ | |||
+ | == See Also == | ||
+ | |||
+ | {{AMC10 box|year=2022|ab=B|num-b=1|num-a=3}} | ||
+ | {{AMC12 box|year=2022|ab=B|num-b=1|num-a=3}} | ||
+ | {{MAA Notice}} |
Revision as of 17:09, 17 November 2022
Problem
In rhombus , point lies on segment so that , , and . What is the area of ? (Note: The figure is not drawn to scale.)
Solution
(Figure redrawn to scale.)
.
is a rhombus, so .
is a 3-4-5 right triangle, so .
The area of the rhombus .
~richiedelgado
See Also
2022 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
2022 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 1 |
Followed by Problem 3 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.