Difference between revisions of "2013 AMC 8 Problems/Problem 4"

(Solution 3 (Pure Algebra))
(Solution 3 (Pure Algebra))
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<cmath>8x=140</cmath>
 
<cmath>8x=140</cmath>
  
~joyoforigami (TOGFA math)
+
~joyoforigami (TOGFA mathematics)
  
 
==Video Solution==
 
==Video Solution==

Revision as of 13:19, 26 December 2022

Problem

Eight friends ate at a restaurant and agreed to share the bill equally. Because Judi forgot her money, each of her seven friends paid an extra $2.50 to cover her portion of the total bill. What was the total bill?

$\textbf{(A)}\ \text{\textdollar}120\qquad\textbf{(B)}\ \text{\textdollar}128\qquad\textbf{(C)}\ \text{\textdollar}140\qquad\textbf{(D)}\ \text{\textdollar}144\qquad\textbf{(E)}\ \text{\textdollar}160$

Solution

Since Judi's 7 friends had to pay 2.50 extra each, to cover the total amount that Judi should have paid, we can multiply 2.50 by 7, which is equal to 17.50. We can now tell that 17.50 is the amount that each of her friends needed to pay, such that Judi didn't forget her money. So, we multiply 17.50 by 8 which is, (C) 140, the total amount of the meal.

Solution 2

Say $m$ is the total amount needed to be paid. At the beginning, each person was supposed to pay $$\frac{m}{8}$. But since Judi forgot her money, we have to add $$\frac{m}{8}$ to $$2.50$ to get the amount of money each of the $7$ friends have to pay. Multiply $$\frac{m}{8} + 2.50$ by $7$ to get $$\frac{7m}{8} + 140$. We can set that equal to $m$ because after we multiply by $7$ we have the total amount needed to be paid. Solving for $m$ we have our answer, $\boxed{\text{(C) } 140}$. ~BananaBall00

Solution 3 (Pure Algebra)

\[8x=7(x+2.5)\] \[8x=7x+17.5\] \[x=17.5.\] \[\text{The problem asked for the total bill, not the price the friends payed.}\] \[8x=140\]

~joyoforigami (TOGFA mathematics)

Video Solution

https://youtu.be/lvaWrFwW6BM ~savannahsolver

See Also

2013 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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