Difference between revisions of "2014 AMC 12A Problems/Problem 2"
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==Problem== | ==Problem== | ||
− | At the theater children get in for half price. The price for <math>5</math> adult tickets and <math>4</math> child tickets is <math>24.50</math>. How much would <math>8</math> adult tickets and <math>6</math> child tickets cost? | + | At the theater children get in for half price. The price for <math>5</math> adult tickets and <math>4</math> child tickets is <math>$24.50</math>. How much would <math>8</math> adult tickets and <math>6</math> child tickets cost? |
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+ | <math>\textbf{(A) }$35\qquad | ||
+ | \textbf{(B) }$38.50\qquad | ||
+ | \textbf{(C) }$40\qquad | ||
+ | \textbf{(D) }$42\qquad | ||
+ | \textbf{(E) }$42.50</math> | ||
== Solution == | == Solution == |
Latest revision as of 16:18, 25 July 2023
Problem
At the theater children get in for half price. The price for adult tickets and child tickets is . How much would adult tickets and child tickets cost?
Solution
Suppose is the price of an adult ticket. The price of a child ticket would be .
Plug in for 8 adult tickets and 6 child tickets.
See Also
2014 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 1 |
Followed by Problem 3 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
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