Difference between revisions of "2022 USAJMO Problems/Problem 1"
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<cmath>g_{l-1}(r-1)^2\equiv0\pmod{m}\text{ (4)}.</cmath> | <cmath>g_{l-1}(r-1)^2\equiv0\pmod{m}\text{ (4)}.</cmath> | ||
− | + | Restating, <math>(1),(2) \textrm{if} (3),(4)</math>, and the conditions <math>g_{l-1}(r-1)\not\equiv 0\pmod{m}</math> and <math>g_{l-1}(r-1)^2\equiv0\pmod{m}</math> hold if and only if <math>m</math> is a perfect square. | |
[will finish that step here] | [will finish that step here] |
Revision as of 22:43, 29 December 2023
Problem
For which positive integers does there exist an infinite arithmetic sequence of integers
and an infinite geometric sequence of integers
satisfying the following properties?
is divisible by
for all integers
;
is not divisible by
.
Solution 1
We claim that satisfies the given conditions if and only if
is a perfect square.
To begin, we let the common difference of be
and the common ratio of
be
. Then, rewriting the conditions modulo
gives:
Condition holds if no consecutive terms in
are equivalent modulo
, which is the same thing as never having consecutive, equal, terms, in
. By Condition
, this is also the same as never having equal, consecutive, terms in
:
Also, Condition holds if
Restating, , and the conditions
and
hold if and only if
is a perfect square.
[will finish that step here]
See Also
2022 USAJMO (Problems • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 | ||
All USAJMO Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.