Difference between revisions of "1960 AHSME Problems/Problem 10"

("see also" section added)
(Solution)
Line 21: Line 21:
  
 
==Solution==
 
==Solution==
<math>\fbox{(C)3}</math>
+
<math>\fbox{(E)5}</math>
Because No men are good negates All men are good.
+
literally e man why u looking at answer key
 
 
  
 
==See Also==
 
==See Also==

Revision as of 17:43, 20 November 2024

Problem 10

Given the following six statements: \[\text{(1) All women are good drivers}\] \[\text{(2) Some women are good drivers}\] \[\text{(3) No men are good drivers}\] \[\text{(4) All men are bad drivers}\] \[\text{(5) At least one man is a bad driver}\] \[\text{(6) All men are good drivers.}\]


The statement that negates statement $(6)$ is:


$\textbf{(A) }(1)\qquad \textbf{(B) }(2)\qquad \textbf{(C) }(3)\qquad \textbf{(D) }(4)\qquad \textbf{(E) }(5)$


Solution

$\fbox{(E)5}$ literally e man why u looking at answer key

See Also

1960 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
All AHSME Problems and Solutions