Difference between revisions of "2008 AMC 12A Problems/Problem 4"
I like pie (talk | contribs) (Formatting of problem, second solution) |
I like pie (talk | contribs) (Added AMC 10 box) |
||
Line 16: | Line 16: | ||
==See Also== | ==See Also== | ||
{{AMC12 box|year=2008|ab=A|num-b=3|num-a=5}} | {{AMC12 box|year=2008|ab=A|num-b=3|num-a=5}} | ||
+ | {{AMC10 box|year=2008|ab=A|num-b=4|num-a=6}} |
Revision as of 23:12, 25 April 2008
Problem
Which of the following is equal to the product
Solution
Solution 1
.
Solution 2
Notice that everything cancels out except for in the numerator and in the denominator.
Thus, the product is , and the answer is .
See Also
2008 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 3 |
Followed by Problem 5 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
2008 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |