Difference between revisions of "2005 PMWC Problems/Problem T10"

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Find the largest 12-digit number for which every two consecutive digits form a distinct 2-digit prime number.
 
Find the largest 12-digit number for which every two consecutive digits form a distinct 2-digit prime number.
  
== Solution ==
+
== Solutions ==
 +
We list all 2 digit primes:
  
This page needs a solution.  The original one, shown below, has an error (denoted by the bolded statement): the number <math>93</math> is certainly not prime; it is divisible by 3.
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11, 13, 17, 19
  
''Original Solution:''
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23, 29
We start with 97, which is the largest 2 digit prime.
 
  
97
+
31, 37
 +
 
 +
41, 43, 47
 +
 
 +
53, 59
  
Then we add 9 to get 79, the largest 2 digit prime with tens digit 7.
+
61, 67
  
979
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71, 73, 79
  
'''Add 3 to get 93, the largest prime less than 97'''
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83, 89
  
9793
+
97
  
Now the largest two digit prime with tens digit 3 is 37. So we add a 7
 
  
97937
+
Picking a 9 would get us:
  
Now we add another 3 as 79 already exists.
+
97371311
  
979373
+
So we pick an 8.
  
And proceeding like this will get us
+
837319737131
  
979373191713
+
That's the greatest.
  
 
== See also ==
 
== See also ==

Revision as of 18:24, 19 September 2008

Problem

Find the largest 12-digit number for which every two consecutive digits form a distinct 2-digit prime number.

Solutions

We list all 2 digit primes:

11, 13, 17, 19

23, 29

31, 37

41, 43, 47

53, 59

61, 67

71, 73, 79

83, 89

97


Picking a 9 would get us:

97371311

So we pick an 8.

837319737131

That's the greatest.

See also

2005 PMWC (Problems)
Preceded by
Problem T9
Followed by
Last Question
I: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
T: 1 2 3 4 5 6 7 8 9 10