Difference between revisions of "1988 AIME Problems/Problem 2"
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Note that this revolves between the two numbers. | Note that this revolves between the two numbers. | ||
| − | <math>f_{1988}(169)=\boxed{169}</math> | + | <math>f_{1988}(169)=169\implies f_{1988}(11)=\boxed{169}</math> |
== See also == | == See also == | ||
{{AIME box|year=1988|num-b=1|num-a=3}} | {{AIME box|year=1988|num-b=1|num-a=3}} | ||
Revision as of 22:02, 26 May 2009
Problem
For any positive integer 
, let 
denote the square of the sum of the digits of . For 
, let 
. Find 
.
Solution
We see that 
Note that this revolves between the two numbers.
See also
| 1988 AIME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
