Difference between revisions of "1988 AJHSME Problems/Problem 2"

(New page: ==Problem== The product <math>8\times .25\times 2\times .125 =</math> <math>\text{(A)}\ \frac18 \qquad \text{(B)}\ \frac14 \qquad \text{(C)}\ \frac12 \qquad \text{(D)}\ 1 \qquad \text{(E...)
 
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==Problem==
 
==Problem==
  
The product <math>8\times .25\times 2\times .125 =</math>
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The [[product]] <math>8\times .25\times 2\times .125 =</math>
  
 
<math>\text{(A)}\ \frac18 \qquad \text{(B)}\ \frac14 \qquad \text{(C)}\ \frac12 \qquad \text{(D)}\ 1 \qquad \text{(E)}\ 2</math>
 
<math>\text{(A)}\ \frac18 \qquad \text{(B)}\ \frac14 \qquad \text{(C)}\ \frac12 \qquad \text{(D)}\ 1 \qquad \text{(E)}\ 2</math>
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==Solution==
 
==Solution==
  
Converting the decimals to fractions, this is  
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Converting the [[Decimal|decimals]] to [[Fraction|fractions]], this is  
 
<cmath>\begin{align*}
 
<cmath>\begin{align*}
 
8\times \frac{1}{4} \times 2\times \frac{1}{8} &= \frac{8\times 2}{4\times 8} \\
 
8\times \frac{1}{4} \times 2\times \frac{1}{8} &= \frac{8\times 2}{4\times 8} \\
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==See Also==
 
==See Also==
  
[[1988 AJHSME Problems]]
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{{AJHSME box|year=1988|num-b=1|num-a=3}}
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[[Category:Introductory Algebra Problems]]

Revision as of 14:38, 1 June 2009

Problem

The product $8\times .25\times 2\times .125 =$

$\text{(A)}\ \frac18 \qquad \text{(B)}\ \frac14 \qquad \text{(C)}\ \frac12 \qquad \text{(D)}\ 1 \qquad \text{(E)}\ 2$

Solution

Converting the decimals to fractions, this is \begin{align*} 8\times \frac{1}{4} \times 2\times \frac{1}{8} &= \frac{8\times 2}{4\times 8} \\ &= \frac{16}{32} \\ &= \frac{1}{2} \rightarrow \boxed{\text{C}} \end{align*}

See Also

1988 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions