Difference between revisions of "2003 AMC 10B Problems/Problem 1"

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==Solution==
 
==Solution==
  
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We can rewrite the given fraction as:
 
We can rewrite the given fraction as:
  

Revision as of 15:57, 31 May 2011

Problem

Which of the following is the same as $\dfrac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}$?

$\textbf{(A)}\ -1 \qquad \textbf{(B)}\ -\frac23 \qquad \textbf{(C)}\ \frac23 \qquad \textbf{(D)}\ 1 \qquad \textbf{(E)}\ \frac{14}{3}$

Solution

We can rewrite the given fraction as:

\[\frac{-3(2)+2(7)}{3(-3)+3(7)}=\frac{2(4)}{3(4)}=\frac{2}{3} \longrightarrow \boxed{\textbf{(C)}}\]

See Also

2003 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
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All AMC 10 Problems and Solutions