Difference between revisions of "2010 AMC 10B Problems/Problem 2"

m (see also and box)
Line 10: Line 10:
 
The total time spent in meetings is <math>45 \text{ min}  + 2*45\text{ min} = 2\text{ hours } 15 \text{ min} = 9/4 \text{ hours}</math>
 
The total time spent in meetings is <math>45 \text{ min}  + 2*45\text{ min} = 2\text{ hours } 15 \text{ min} = 9/4 \text{ hours}</math>
  
Therefore, the percentage is <cmath>\frac{9/4 \text{ hours} }{9 \text{ hours}} = \frac{1}{4} = 25 \% = {(C)} 25}</cmath>
+
Therefore, the percentage is <cmath>\frac{9/4 \text{ hours} }{9 \text{ hours}} = \frac{1}{4} = 25 \% = \boxed{\textbf{(C)} 25}</cmath>
 +
 
 +
==See Also==
 +
{{AMC10 box|year=2010|ab=B|num-b=1|num-a=3}}

Revision as of 00:49, 26 November 2011

Problem

Makarla attended two meetings during her $9$-hour work day. The first meeting took $45$ minutes and the second meeting took twice as long. What percent of her work day was spent attending meetings?

$\textbf{(A)}\ 15 \qquad \textbf{(B)}\ 20 \qquad \textbf{(C)}\ 25 \qquad \textbf{(D)}\ 30 \qquad \textbf{(E)}\ 35$

Solution

The percentage of her time spent in meetings is the total amount of time spent in meetings divided by the length of her workday.

The total time spent in meetings is $45 \text{ min}  + 2*45\text{ min} = 2\text{ hours } 15 \text{ min} = 9/4 \text{ hours}$

Therefore, the percentage is \[\frac{9/4 \text{ hours} }{9 \text{ hours}} = \frac{1}{4} = 25 \% = \boxed{\textbf{(C)} 25}\]

See Also

2010 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions