Difference between revisions of "1997 PMWC Problems/Problem I13"
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Therefore the distance from A to B is <math>\frac{5}{2}*70=\boxed{175}</math>. | Therefore the distance from A to B is <math>\frac{5}{2}*70=\boxed{175}</math>. | ||
| − | == See | + | == See Also == |
{{PMWC box|year=1997|num-b=I12|num-a=I14}} | {{PMWC box|year=1997|num-b=I12|num-a=I14}} | ||
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
Revision as of 15:05, 15 May 2012
Problem
A truck moved from A to B at a speed of 50 km/h and returns from B to A at 70 km/h. It traveled 3 rounds within 18 hours. What is the distance between A and B?
Solution
The truck moved from A to B back and forth once in 18/3=6 hours. Let the time that it takes to go from A to B be 
, and let the time it takes to go from B to A be 
.
Therefore the distance from A to B is 
.
See Also
| 1997 PMWC (Problems) | ||
| Preceded by Problem I12 |
Followed by Problem I14 | |
| I: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 T: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
