Difference between revisions of "1991 AHSME Problems/Problem 3"

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== Solution ==
 
== Solution ==
<math>\fbox{}</math>
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<math>\fbox{A}</math>
  
 
== See also ==
 
== See also ==

Revision as of 14:50, 28 September 2014

Problem

$(4^{-1}-3^{-1})^{-1}=$

(A) $-12$ (B) $-1$ (C) $\frac{1}{12}$ (D) $1$ (E) $12$

Solution

$\fbox{A}$

See also

1991 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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