Difference between revisions of "2015 AMC 12A Problems/Problem 1"
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==Solution== | ==Solution== | ||
− | + | Evaluating, we have <math>(2^0-1+5^2-0)^{-1}\times5</math> = <math>(1-1+25-0)^{-1}\times5</math> = <math>(25)^{-1}\times5</math> = <math>\frac{5}{25}</math> = <math>\boxed{\textbf{(C)}\frac15}</math>. | |
Revision as of 14:26, 4 February 2015
Problem
What is the value of
$\textbf{(A)}\ -125\qquad\textbf{(B)}\ -120\qquad\textbf{(C)}\ \frac{1}{5}\qquad\textbf{(D)}}\ \frac{5}{24}\qquad\textbf{(E)}\ 25$ (Error compiling LaTeX. Unknown error_msg)
Solution
Evaluating, we have = = = = .
2015 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by First Question |
Followed by Problem 2 |
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All AMC 12 Problems and Solutions |
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