Difference between revisions of "2013 AMC 8 Problems/Problem 4"
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==Solution== | ==Solution== | ||
| − | Each of her seven friends paid <math>\text{\textdollar}2.50</math> to cover Judi's portion. Therefore, Judi's portion must be <math>\text{\textdollar}2.50 \cdot 7</math>. Since | + | Each of her seven friends paid <math>\text{\textdollar}2.50</math> to cover Judi's portion. Therefore, Judi's portion must be <math>\text{\textdollar}2.50 \cdot 7 = {\textdollar}17.50</math>. Since each friend was supposed to pay the same amount, each friend was supposed to pay <math>\frac{1}{8}</math> of the total bill; the total bill must be <math>8 \cdot 7 \cdot \text{\textdollar}2.50 = \boxed{\textbf{(C)} \ \text{\textdollar}140}</math>. |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2013|num-b=3|num-a=5}} | {{AMC8 box|year=2013|num-b=3|num-a=5}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 17:11, 11 November 2015
Problem
Eight friends ate at a restaurant and agreed to share the bill equally. Because Judi forgot her money, each of her seven friends paid an extra $2.50 to cover her portion of the total bill. What was the total bill?
Solution
Each of her seven friends paid 
to cover Judi's portion. Therefore, Judi's portion must be 
. Since each friend was supposed to pay the same amount, each friend was supposed to pay 
of the total bill; the total bill must be 
.
See Also
| 2013 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
