Difference between revisions of "1988 AJHSME Problems/Problem 23"
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==Problem== | ==Problem== | ||
− | Maria buys computer disks at a price of <math>4</math> for <math> | + | Maria buys computer disks at a price of <math>4</math> for <math>$5</math> and sells them at a price of <math>3</math> for <math>$5</math>. How many computer disks must she sell in order to make a profit of <math>$100</math>? |
<math>\text{(A)}\ 100 \qquad \text{(B)}\ 120 \qquad \text{(C)}\ 200 \qquad \text{(D)}\ 240 \qquad \text{(E)}\ 1200</math> | <math>\text{(A)}\ 100 \qquad \text{(B)}\ 120 \qquad \text{(C)}\ 200 \qquad \text{(D)}\ 240 \qquad \text{(E)}\ 1200</math> | ||
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==Solution== | ==Solution== | ||
− | This is the equivalent of saying she buys <math>12</math> for | + | This is the equivalent of saying she buys <math>12</math> for <math>$15</math> and sells <math>12</math> for <math>$20</math>, so for every dozen disks she sells, she profits <math>$5</math>. |
− | She needs to profit | + | She needs to profit <math>$100</math>, so she needs to sell <math>\frac{100}{5}=20</math> dozen disks, which is <math>240\rightarrow \boxed{\text{D}}</math> |
==See Also== | ==See Also== |
Latest revision as of 17:46, 24 June 2016
Problem
Maria buys computer disks at a price of for and sells them at a price of for . How many computer disks must she sell in order to make a profit of ?
Solution
This is the equivalent of saying she buys for and sells for , so for every dozen disks she sells, she profits .
She needs to profit , so she needs to sell dozen disks, which is
See Also
1988 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 22 |
Followed by Problem 24 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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